Jika bilangan real a dan b memenuhi persamaan xlog4+2logx=3, maka a+b
Matematika
suryani1998
Pertanyaan
Jika bilangan real a dan b memenuhi persamaan xlog4+2logx=3, maka a+b
1 Jawaban
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1. Jawaban 18Navillera
ˣlog 4 + ²log x =3
ˣlog 2² + ²log x = 3
2 . ˣlog 2 + ²log x =
2 . ˣlog 2 + 1/ˣ log2 = 3
misal ˣlog 2 = p
2p + 1/p = 3
------------------- × p
2p² + 1 = 3p
2p² - 3p + 1 = 0
p1,2 = (-b +/- √(b² - 4ac))/2a
p1,2 = (3 +/- √(9 - 8))/4
p1,2 = (3 +/- 1)/4
p1 = 4/4 = 1
p2 = 2/4 = 1/2
ˣlog 2 = 1
x¹ = 2
x = 2 = a
ˣlog 2 = 1/2
x^1/2 = 2
x = 4 = b
∴ a + b = 2 + 4 = 6