tolong kasih jawaban ya

[tex]f(2x-1) =4x + 7 \\ f(-5) = ? \\ \\ f(-5)=f(2x-1) \\ -5=2x-1 \\ 2x=-4 \\ x=-2 \\ \\ f(-2)=4(-2)+7 \\ f(-2)=-8+7 \\ f(-2)=-1[/tex]

[tex]f(2x - 1) = 4x + 7 \\\\ misal 2x - 1 = a\\x = \frac{a + 1}{2} \\\\Substitusi...\\f(a) = 4 (\frac{a+1}{2}) + 7\\f(-5) = 4( \frac{-5+1}{2}) + 7\\f(-5) = 4( \frac{-4}{2}) + 7\\f(-5) = 4(-2) + 7\\f(-5) = -8 + 7\\f(-5) = -1[/tex]

[tex] \left[\begin{array}{ccc}Opsi B\end{array}\right] [/tex]