Lim x->4 dari x²-16 / x²+16

[tex]\displaystyle \lim_{x\to4}\frac{x^2-16}{x^2+16}=\frac{4^2-16}{4^2+16}\\\lim_{x\to4}\frac{x^2-16}{x^2+16}=\frac{16-16}{16+16}\\\boxed{\boxed{\lim_{x\to4}\frac{x^2-16}{x^2+16}=0}}[/tex]

Matematika XI SMA
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Pembahasan :
Lim [x » 4] (x² - 16)/(x² + 16)

Substitusi x = 4, sehingga...
(4² - 16)/(4² + 16)
= (16 - 16)/(16 + 16)
= 0/32
= 0