tolong bantuin donggg :

[2log(2x - 3)]/[2logx] - xlog(x + 6) + 1/((x + 2)logx) = 1
=> xlog(2x - 3) - xlog(x + 6) + xlog(x + 2) = xlogx
=> xlog(2x - 3) + xlog(x + 2) = xlog(x + 6) + xlogx
=> xlog(2x - 3)(x + 2) = xlog(x + 6)x
=> (2x - 3)(x + 2) = x(x + 6)
=> 2x^2 + 4x - 3x - 6 = x^2 + 6x
=> x^2 - 5x - 6 = 0
=> (x - 6)(x + 1) = 0
=> x = 6 atau x = -1

Syarat logaritma : (x + 2)logx => x > 0

Maka x yang memenuhi => x = 6