Matematika

Pertanyaan

a. diketahui tan B = 6/8, nilai sin B = ....?
b. diketahui cos A = 4/5, nilai cot A = ....?

bantu ya, terima kasih !!!

2 Jawaban

  • a.
    tan B = 6/8 = y/x
    ⇒r² = 6² + 8²
    ⇒r² = 100
    ⇒r = 10

    sin B = y/r
    sin B = 6/10 = 3/5

    b.
    cos A = 4/5 = x/r
    ⇒y² = 5² - 4²
    ⇒y² = 9
    ⇒y = 3

    cot A = x/y
    cot A = 4/3
  • [tex]\displaystyle \tan b=\frac68\\\frac yx=\frac34\\\\y=3\\x=4\\r=\sqrt{x^2+y^2}\\=5\\\\\sin b=\frac{y}{r}\\\boxed{\boxed{\sin b=\frac35}}\\\\\cos a=\frac45\\\frac xr=\frac45\\\\x=4\\r=5\\y=\sqrt{r^2-x^2}\\y=3\\\\\cot a=\frac{x}{y}\\\boxed{\boxed{\cot a=\frac43}}[/tex]

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