Sebuah kubus besi bersisi 10 cm. setelah ditimbang , masanya 1 kg. Hitung lah massa jenis  dan besar tekanan yang dialami meja jika kubus besi tersebut diletakk

[tex]\displaystyle s=0,1\,\text{m}\\m=1\,\text{kg}\\g=10\,\text{m/s}^2\\\\\rho=?\\p=?\\\\\rho=\frac{m}{V}\\\rho=\frac{m}{s^3}\\\rho=\frac{1}{(0,1)^3}\\\rho=\frac{1}{\frac{1}{1000}}\\\boxed{\boxed{\rho=1000\,\text{kg/m}^3}}\\\\p=\frac{F}{A}\\p=\frac{mg}{s^2}\\p=\frac{1\cdot10}{(0,1)^2}\\p=\frac{10}{0,01}\\\boxed{\boxed{p=1000\,\text{N/m}^2}}[/tex]

Diberikan
V = 10 x 10 x 10 = 1000 cm^3
m = 1 kg = 1000 g
L permukaan = 10 x 10 = 100 cm^2 = 0,01 m^2
F = mg = 1 × 10 = 10 N

a. massa jenis
p = m/V = 1000/1000 = 1 g/cm^3

b. tekanan
P = F/A = 10/0,01 = 1000 Pascal