gimana cara menyelesaikan spldv ini?

2x - 3y = -1
2x = 3y - 1
x = (3y - 1)/2

2x^2 - 3y^2 = 5
2((3y - 1)/2)^2 - 3y^2 = 5
2(9y^2 - 6y + 1)/4 - 3y^2 = 5 =====> kedua ruas kali 2
9y^2 - 6y + 1 - 6y^2 = 10
3y^2 - 6y - 9 = 0
y^2 - 2y - 3 = 0
(y - 3)(y + 1) = 0
y = 3 atau y = -1
x = (3y - 1)/2
y = 3 => x = (3.3 - 1)/2 = (9 - 1)/2 = 8/2 = 4 => (4, 3)
y = -1 => x = (3.-1 - 1)/2 = (-3 - 1)/2 = -4/2 = -2 => (-2, -1)
HP = {(-2, -1), (4, 3)}

Matematika SMA
SPLKDV

Pembahasan :
2x² - 3y² = 5 —» y = √[(2x² - 5)/3]
2x - 3y = 1 —» y = (2x - 1)/3

Samakan...
y = y
√[(2x² - 5)/3] = (2x - 1)/3
(2x² - 5)/3 = (2x - 1)²/9
9(2x² - 5) = 3(4x² - 4x + 1)
18x² - 45 = 12x² - 12x + 3
6x² + 12x - 48 = 0
x² + 2x - 8 = 0
(x + 4)(x - 2) = 0
x = -4 V x = 2

Untuk x = -4, maka...
2x - 3y = 1
2(-4) - 3y = 1
-8 - 3y = 1
3y = -9
y = -3

Untuk x = 2, maka...
2x - 3y = 1
2(2) - 3y = 1
3y = 4 - 1
3y = 3
y = 1

Jadi...
Hp : {(-4 , -3) , (2 , 1)}