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Bab Differensial
Matematika SMA Kelas XI

y = (3/4) x⁴ + 2x³ + (1/2) x² + x + 15
y' = 4 . (3/4) . x³ + 3 . 2x² + 2 .(1/2) x
y" = 3 . 3x² + 2 . 6x + 1
y" (2) = 9 . 2² + 12 . 2 + 1
y" (2) = 36 + 24 + 1
y" (2) = 61

jawabannya C

[tex]y= \frac{3}{4}x^{4} + 2 x^{3} + \frac{1}{2} x^{2} + x + 15 \\ y' = 4( \frac{3}{4}) x^{3} + 3(2) x^{2} + 2( \frac{1}{2} )x +1(1) \\ y' = 3 x^{3} + 6 x^{2} + x + 1 \\ y'' = 3(3) x^{2} + 2(6)x + 1(1) \\ y'' = 9 x^{2} + 12x + 1 \\ y''(2) = 9(2) ^{2} + 12(2) + 1 \\ y''(2) = 61[/tex]