jika hiperbola [(x^2-2nx-n^2)/25] -[(y^2-2my+m^2)/16] = 1, memiliki asimtot yang memotong sumbu y dititik (0,1), maka 5m-4n = ...

Ralat : seharusnya (+ n^2)
(x^2 - 2nx + n^2)/25 - (y^2 - 2my + m^2)/16 = 1
(x - n)^2 / 25 - (y - m)^2 / 16 = 1
persamaan Asimtot
(x - n)^2 / 25 - (y - m)^2 / 16 = 0
(x - n)^2 / 25 = (y - m)^2 / 16
(x - n)^2 = (25/16) (y - m)^2
(x - n) = ± 5/4 (y - m)
4(x - n) = ± 5(y - m)
memotong sumbu y di (0, 1)
4(0 - n) = ± 5(1 - m)
1) -4n = 5 - 5m => 5m - 4n = 5 ===> jawaban
2) -4n = -5 + 5m => 5m + 4n = 5