Nomor 6 dan 5 yaa tolongg sama caranyaa

6) puncak = (-2, 3) dan (-2, 9) => x nya sama maka sumbu utama nya sejajar sumbu y
Misal pusat = (p, q)
Puncak = (p, q + a) dan (p, q - a) => (-2, 3) dan (-2, 9)
p = -2
q - a = 3
q + a = 9
----------- +
2q = 12 => q = 6
q - a = 3 => 6 - a = 3 => a = 3 => a^2 = 9
Pusat hiperbola = (p, q) = (-2, 6)

Fokus = (p, q + c) dan (p, q - c) = (-2, 6 + c) dan (-2, 6 - c)

Puncak terletak ditengah-tengah pusat dan fokus
Puncak = 1/2 (pusat + fokus)
2 puncak = pusat + fokus
Fokus = 2 puncak - pusat

1) puncak = (-2, 3) , pusat (-2, 6)
Fokus = 2(-2, 3) - (-2, 6) = (-4, 6) - (-2, 6) = (-2, 0)
=> (p, q - c) = (-2, 6 - c)
=> (-2, 0) = (-2, 6 - c)
=> 0 = 6 - c
=> c = 6
2) puncak (-2, 9), pusat (-2, 6)
Fokus = 2(-2, 9) - (-2, 6) = (-4, 18) - (-2, 6) = (-2, 12)
=> (p, q + c) = (-2, 6 + c)
=> (-2, 12) = (-2, 6 + c)
=> 12 = 6 + c
=> c = 6

b^2 = c^2 - a^2 = 36 - 9 = 27

Persamaan hiperbola
(y - q)^2 / a^2 - (x - p)^2 / b^2 = 1
(y - 6)^2 / 9 - (x + 2)^2 / 27 = 1
- (x + 2)^2 / 27 + (y - 6)^2 / 9 = 1

No. 5 sudah di jawab di soal yg sudah di post sebelumnya