tolong bantuin ya ?........

3.√2+2+2+2√2+4+4√2=8+7√2
4.a/3x³-3x²+5x+c=15
8a/3-12+10+c=15
8a/3+c=17
8a+3c=51 pers 1...

-a/3-3-5+c=15
-a/3+c=23
-a+3c=69 pers 2....

8a+3c=51
-a+3c=69
9a=-18
a=-2

2) √2 + √4 + '3√8 + √8 + √16 + √32
= √2 + 2 + 2 + √(4.2) + 4 + √(16.2)
= √2 + 4 + 2√2 + 4 + 4√2
= 8 + 7√2

3) (batas -1 s.d 2) ∫ (ax^2 - 6x + 5) dx = 15
a/3 x^3 - 6/2 x^2 + 5x | = 15
(a/3) x^3 - 3x^2 + 5x | = 15 ====> masukkan batas x = 2 dikurang x = -1
((a/3) (2)^3 - 3(2)^2 + 5(2)) - ((a/3)(-1)^3 - 3(-1)^2 + 5(-1)) = 15
(8a)/3 - 12 + 10 - (-a/3 - 3 - 5) = 15
(8a)/3 - 2 + a/3 + 8 = 15
9a/3 + 6 = 15
3a = 9
a = 3