Tolong jawab........... Thanks

f(x) = (2x+4)/(1+√x)

f(x) = u/v
f'(x) = (u'v - v'u)/v²

u = 2x+4
u' = 2

v = 1+√x
v' = 1/(2√x)

f'(x) = (2(1+√x) - (1/(2√x))(2x+4))/(1+√x)²

subtitusi x=4
f'(4) = (2(1+√4)-(1/(2√4))((2.4)+4))/(1+√4)²
= (6-3)/(3)²
= 3/9
= 1/3

maaf kalau salah