Tolong dijawab dengan caranya

px^2 + px + r = 0
x1 . x2 = c/a = r/p
x1 - x2 = |√D/a| = |√(b^2 - 4ac) / a| = |√(p^2 - 4pr) / p|

1/(x1^2.x2) - 1/(x1.x2^2)
= (x2 - x1) / (x1^2.x2^2)
= |√(p^2 - 4pr)/p| / (x1.x2)^2
= |√(p^2 - 4pr)/p| : (r/p)^2
= |√(p^2 - 4pr)/p| . (p^2)/(r^2)
= |p√(p^2 - 4pr) / r^2|
= (p/r^2) √(p^2 - 4pr) atau -(p/r^2) √(p^2 - 4pr)