nomor 8 dan 9 beserta caranya ...

[tex]\displaystyle 9\\\^3\log(x-2)-^3\log(x-4)=^3\log(x-2)\\-^3\log(x-4)=0\\^3\log(x-4)=0\\x-4=3^0\\x-4=1\\x=5\\\\\boxed{\boxed{\text{HP}=\{5\}}}[/tex]

[tex]\displaystyle 8\\^3\log a=2\\a=3^2\\a=9\\\\\frac1{81}(((a^2)^3)^4)^\frac18=\frac1{81}(9^{2\cdot3\cdot4\cdot\frac18})\\\frac1{81}(((a^2)^3)^4)^\frac18=\frac1{9^2}(9^3)\\\boxed{\boxed{\frac1{81}(((a^2)^3)^4)^\frac18=9}}[/tex]

Bab Logaritma
Matematika SMA Kelas X

8] ³log a = 2
a = 3² = 9

(((a²)³)⁴)^(1/8) . 1/81
= (9)^(2 x 3 x 4 / 8) . 1/81
= 9^3 . 1/81
= 729 x 1/81
= 9

jawabannya B

9] ³log (x - 2) - ³log (x - 4) = ³log (x - 2)
³log (x - 4) = ³log (x - 2) - ³log (x - 2)
x - 4 = 3⁰
x = 1 + 4
x = 5

syarat, 
x - 2 > 0
x > 2

maka, jawabannya x = 5