tlng jwb no 93 & 95

Semoga membantu
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Mapel : Matematika
Kelas : VII SMP
Bab : Aljabar

Pembahasan :
93||

a/2 = b/3
3a = 2b

b/3 = c/5
5b = 3c ——» b = 3/5 c

a/2 = c/5
5a = 2c ——» a = 2/5 c

Maka...
(a + b + c)/c
= (2/5C + 3/5C + C)/c
= (10/5 C)/C
= 2

95||

[(3,79)² - (1,21)²]/(5 x 1,31 + 5 x 1,27)
= [(3,79 + 1,21)(3,79 - 1,21)]/[5(1,31 + 1,27)]
= [(5)(2,58)]/[5(2,58)]
= 1