Matematika

Pertanyaan

can anyone help me with this question thx!
can anyone help me with this question thx!

2 Jawaban

  • [tex]\displaystyle \text{BE}=2\text{DE}\\\text{BE}=2\cdot10\\\text{BE}=20\\\\\text{BE}^2=\text{DE}^2+\text{BD}^2\\20^2=10^2+\text{BD}^2\\400=100+\text{BD}^2\\300=\text{BD}^2\\10\sqrt3=\text{BD}\\\\K_{\Delta\text{BDE}}=\text{DE}+\text{BE}+\text{BD}\\K_{\Delta\text{BDE}}=10+20+10\sqrt3\\\boxed{\boxed{K_{\Delta\text{BDE}}=30+10\sqrt3}}[/tex]
  • DE = SISI ALAS ( x ) = 10
    DB = SISI TEGAK ( x√3 ) = ....?
    BE = SISI MIRING (2x) = .....?

    Panjang DB =
    x√3 =
    10√3 ( satuan )

    panjang BE =
    2x =
    2(10) =
    20 (satuan)

    Keliling = DE + DB + BE
    Keliling = 10 + 10√3 + 20
    Keliling = 30 + 10√3
    Keliling = 10 ( 3 + √3)

    #semoga membantu....