mohon jawabannya ya soal ada di gambarrr

Mapel : Matematika
Kelas : X SMA
Bab : Eksponen dan Logaritma

Pembahasan :
⁴√[81/16] - 3√[1/9] + √[64/100]
= 3/2 - 3(1/3) + 8/10
= 3/2 - 1 + 8/10
= (15 - 10 + 8)/10
= 13/10

Opsi B.

[tex]\displaystyle \sqrt[4]{\frac{81}{16}}-3\sqrt{\frac19}+\sqrt{\frac{64}{100}}=\frac{3}{2}-3\cdot\frac13+\frac{8}{10}\\\sqrt[4]{\frac{81}{16}}-3\sqrt{\frac19}+\sqrt{\frac{64}{100}}=\frac{3}{2}-1+\frac{8}{10}\\\sqrt[4]{\frac{81}{16}}-3\sqrt{\frac19}+\sqrt{\frac{64}{100}}=\frac{1}{2}+\frac{8}{10}\\\sqrt[4]{\frac{81}{16}}-3\sqrt{\frac19}+\sqrt{\frac{64}{100}}=\frac{5}{10}+\frac{8}{10}\\\boxed{\boxed{\sqrt[4]{\frac{81}{16}}-3\sqrt{\frac19}+\sqrt{\frac{64}{100}}=\frac{13}{10}}}[/tex]