tolong di bntu ya beserta caranya terima kasih

Mapel : Matematika
Kelas : X SMA
Bab : Eksponen dan Logaritma

Pembahasan :
3^(2m + 1) = 12
3^(2m) = 4
(3^m)² = 4
(3^m) = 2

Maka...
3^(3m - 1) - 3^(m - 1)
= 3^(3m)/3 - (3^m)/3
= [3^(3m) - 3^m]/3
= [2^3 - 2]/3
= (8 - 2)/3
= 6/3
= 2

Opsi C.

Bab Logaritma
Matematika SMA Kelas X

3^(2m + 1) = 12
3^log 12 = 2m + 1
3log 3 + 3^log 4 = 2m + 1
1 + 3^log 4 = 2m + 1
3^log 4 = 2m
m = (1/2) . 3^log 4
m = 3^log 2
3^m = 2

3^(3m - 1) - 3^(m - 1)
= (3^(3m) . 1/3 ) - (3^m) . 1/3
= 1/3 . (2^3 - 2)
= 1/3 . (8 - 2)
= 1/3 . 6
= 2

◎◎ C ◎◎