tolonggg bantu jawabin ini yaaa

[tex]\displaystyle \lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}=\lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}\cdot\frac{\sqrt{2+\sqrt[4]{x}}+2}{\sqrt{2+\sqrt[4]{x}}+2}\\\lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}=\lim_{x\to16}\frac{(\sqrt x-4)(\sqrt{2+\sqrt[4]{x}}+2)}{2+\sqrt[4]{x}-4}\\\lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}=\lim_{x\to16}\frac{(\sqrt x-4)(\sqrt{2+\sqrt[4]{x}}+2)}{\sqrt[4]{x}-2}\cdot\frac{\sqrt[4]{x}+2}{\sqrt[4]{x}+2}[/tex]
[tex]\displaystyle \lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}=\lim_{x\to16}\frac{(\sqrt x-4)(\sqrt{2+\sqrt[4]{x}}+2)(\sqrt[4]{x}+2)}{\sqrt{x}-4}\\\lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}=\lim_{x\to16}(\sqrt{2+\sqrt[4]{x}}+2)(\sqrt[4]{x}+2)\\\lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}=(\sqrt{2+\sqrt[4]{16}}+2)(\sqrt[4]{16}+2)\\\lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}=(2+2)(2+2)\\\boxed{\boxed{\lim_{x\to16}\frac{\sqrt x-4}{\sqrt{2+\sqrt[4]{x}}-2}=16}}[/tex]