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Bab Integral
Matematika SMA Kelas XI

∫²₋₂ (x³ - 6x² + 8x + 2) dx
= (1/4 x⁴ - 2x³ + 4x² + 2x) |²₋₂
= (1/4 . 2⁴ - 2 . 2³ + 4 . 2² + 2 . 2) - (1/4 . (-2)⁴ - 2 . (-2)³ + 4 . (-2)² + 2 . (-2))
= (1/4 . 16 - 16 + 16 + 4) - (1/4 . 16 + 16 + 16 - 4)
= -32 + 8
=  -24

Integral Tentu

∫²₋₂ (x³ - 6x² + 8x + 2) dx
= 1/(3+1) x³⁺¹ - 6/(2+1) x²⁺¹ + 8/(1+1) x¹⁺¹ + 2x
= 1/4x⁴ - 2x³ + 4x² + 2x
= [1/4 (2)⁴ - 2 (2)³ + 4 (2)² + 2 (2)] - [1/4 (-2)⁴ - 2 (-2)³ + 4 (-2)² + 2 (-2)]
= [1/4 (16) - 2 (8) + 4 (4) + 4] - [1/4 (16) - 2 (-8) + 4 (4) - 4]
= (4 - 16 + 16 + 4) - (4 + 16 + 16 - 4)
= 8 - (32)
= -24