bentuk sederhana dari -12/√3-√2 adalah..

[tex]\displaystyle \frac{-12}{\sqrt3-\sqrt2}=\frac{-12}{\sqrt3-\sqrt2}\cdot\frac{\sqrt3+\sqrt2}{\sqrt3+\sqrt2}\\\frac{-12}{\sqrt3-\sqrt2}=\frac{-12(\sqrt3+\sqrt2)}{3-2}\\\frac{-12}{\sqrt3-\sqrt2}=\frac{-12(\sqrt3+\sqrt2)}{1}\\\boxed{\boxed{\frac{-12}{\sqrt3-\sqrt2}=-12(\sqrt3+\sqrt2)}}[/tex]

Mapel : Matematika
Kelas : IX SMP
Materi : Merasionalkan bentuk akar

Pembahasan :
-12/(√3 - √2)
= -12/[-(√2 - √3)]
= 12/(√2 - √3)
= 12/(√2 - √3) x (√2 + √3)/(√2 + √3)
= 12(√2 + √3)/(2 - 3)
= 12(√2 + √3)/(-1)
= -12(√2 + √3)
= -12√2 - 12√3