bentuk sederhana 3-√7/3+√7

[tex]\displaystyle \frac{3-\sqrt7}{3+\sqrt7}=\frac{3-\sqrt7}{3+\sqrt7}\cdot\frac{3-\sqrt7}{3-\sqrt7}\\\frac{3-\sqrt7}{3+\sqrt7}=\frac{(3-\sqrt7)^2}{9-7}\\\frac{3-\sqrt7}{3+\sqrt7}=\frac{16-6\sqrt7}{2}\\\boxed{\boxed{\frac{3-\sqrt7}{3+\sqrt7}=8-3\sqrt7}}[/tex]

Mapel : Matematika
Kelas : IX SMP
Materi : Merasionalkan bentik akar

Pembahasan :
(3 - √7)/(3 + √7)
= (3 - √7)/(3 + √7) . (3 - √7)/(3 - √7)
= (3 - √7)²/[(3 + √7)(3 - √7)
= (9 - 6√7 + 7)/(9 - 7)
= (16 - 6√7)/(2)
= 8 - 3√7