saya dulu dapat jawaban yang benar sekarang saya coba jawab saya lupa caranya, tolong caranya yah ka.

[tex]\displaystyle V=\pi r^2t\\V=\pi\left(\frac{\sqrt2-1}{\sqrt2+1}\right)^2\cdot\frac{6\sqrt3}{2\sqrt2+3}\\V=\pi r^2t\\V=\pi\left(\frac{\sqrt2-1}{\sqrt2+1}\cdot\frac{\sqrt2-1}{\sqrt2-1}\right)^2\cdot\frac{6\sqrt3}{2\sqrt2+3}\cdot\frac{2\sqrt2-3}{2\sqrt2-3}\\V=\pi\left(\frac{(\sqrt2-1)^2}{2-1}\right)^2\cdot\frac{6\sqrt3(2\sqrt2-3)}{8-9}\\V=\pi\left(3-2\sqrt2\right)^2\cdot\frac{12\sqrt6-18\sqrt3}{-1}\\V=\pi\left(17-12\sqrt2\right)\left(18\sqrt3-12\sqrt6\right)[/tex]
[tex]\displaystyle V=(306\sqrt3-204\sqrt6-216\sqrt6+144\sqrt{12})\pi\\\boxed{\boxed{V=(594\sqrt3-420\sqrt6)\pi}}[/tex]