Matematika

Pertanyaan

U1=k-1,U3=3k+1,U10=98.U6=...

2 Jawaban

  • Mapel : Matematika
    Kelas : IX SMP
    Bab : Barisan dan deret

    Pembahasan :
    2(U2) = U1 + U3
    2(U2) = (k - 1) + (3k + 1)
    2U2 = 4k
    U2 = 2k

    Beda = U2 - U1
    Beda = 2k - (k - 1)
    Beda = 3k + 1

    U10 = 98
    a + 9b = 98
    k - 1 + 9(3k + 1) = 98
    k - 1 + 27k + 9 = 98
    28k + 8 = 98
    28k = 90
    k = 90/28
    k = 45/14

    Beda = 3k + 1
    Beda = 3(45/14) + 1
    Beda = 149/14

    a = k - 1
    a = 45/14 - 1
    a = 31/14

    U6 = a + 5b
    U6 = 31/14 + 5(149/14)
    U6 = 31/14 + 745/14
    U6 = 766/14
    U6 = 383/7
  • dik:
    U1=k-1
    U3=3k+1
    U10=98

    U2=U1-b
    =k-1-b
    b=?

    dit:
    U6=?

    jwb:
    U3-U2
    =U2-U1
    =3k+1-(k-1+b)
    =(k-1+b)-(k-1)
    =3k-k+1+1
    =2b 2k+2=2b

    b=k+1 U10
    =a+9b 98
    =(k-1)+9(k+1) 98
    =k-1+9k+9 98
    =10k+8 98-8
    =10K 90
    =10k 90/10
    =k
    k=9 U1
    =a=k-1=9-1=8
    b=k+1=9+1=10
    U6=a+5b
    U6=8+5×10
    U6=8+50
    U6=58

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