[tex]SinA+CosA=???[/tex] Tentukan Jika A = 12 B = 13 C = 25

A = 12
B = 13
C = 25

Cos A = [B^2 + C^2 - A^2]/[2BC]
Cos A = [13^2 + 25^2 - 12^2]/[2 × 13 × 25]
Cos A = [169 + 625 - 144]/[650]
Cos A = 650/650
Cos A = 1
Sin^2 A = 1 - Cos^2 A
Sin^2 A = 1 - 1^2
Sin^2 A = 1 - 1
Sin A = akar 0
Sin A = 0

maka :
Sin A + Cos A = 0 + 1 = 1
Jadi nilai Sin A + Cos A adalah 1