tolong bantu ya kakak-kakak

[tex]\displaystyle (f\circ g)(x)=\frac{\sqrt{4x^2+24x+35}}{x+3}\\(f\circ g)(x)=\sqrt{\frac{4x^2+24x+35}{x^2+6x+9}}\\(f\circ g)(x)=\sqrt{\frac{4x^2+24x+36-1}{x^2+6x+9}}\\(f\circ g)(x)=\sqrt{\frac{4x^2+24x+36}{x^2+6x+9}-\frac{1}{x^2+6x+9}}\\(f\circ g)(x)=\sqrt{4-\left(\frac{1}{x+3}\right)^2}\\\sqrt{4-\left(g(x)\right)^2}=\sqrt{4-\left(\frac{1}{x+3}\right)^2}\\g(x)=\frac{1}{x+3}\\\\g(1-2x)=\frac{1}{1-2x+3}\\\boxed{\boxed{g(1-2x)=\frac{1}{4-2x}}}[/tex]