dik: 2log 7 = a , 2log 3 =b dit: 6log 28² =?

Pakai sifat :
^a log b = (^c log b) / (^c log a)

^6 log 28^2
= 2 × ^6 log 28
= 2 × ((^2 log 28) / (^2 log 6))
= 2 × ( (^2 log (7×4) ) / (^2 log (3×2))
= 2 × ( ^2 log 7 + ^2 log4) / (^2 log 3 + ^2 log 2)
= 2 × (a + 2) / (b + 1)
= (2a + 4) / (b + 1)

Bab Logaritma
Matematika SMA Kelas X

⁶log 28² = (²log 28²) / (²log 6)
⁶log 28² = (2 . ²log (7 . 2 . 2)) / (²log (3 . 2))
⁶log 28² = (2 . (²log 7 + ²log 2 + ²log 2)) / (²log 3 + ²log 2)
⁶log 28² = (2 . (a + 1 + 1) / (b + 1)
⁶log 28² = (2a + 4) /(b + 1)

jawabannya D