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DINAMIKA
• gerak dan gaya

m = 100 kg
g = 10 m/s²... ANGGAP
F = 600 N, α = 37°
us = 0,6. uk = 0,4
Vo = 0
t = 2 s

gaya berat
w = m g
w = 100 • 10 = 1000 N

komponen gaya F, α
Fx = F cos 37°
Fx = 600 • 0,8 = 480 N
Fy = F sin 37°
Fy = 600 • 0,6 = 360 N

gaya normal
N = w - Fy
N = 1000 - 360 = 640 N

gaya gesek
fs = us N
fs = 0,6 • 640 = 384 N ← jwb (3)
fk = uk N
fk = 0,4 • 640 = 256 N

Karena Fx > fs maks, benda bergerak. ← jwb (1)

Percepatan
Fx - fk = m a
480 - 256 = 100 a
224 = 100 a
a = 2,24 m/s²

kecepatan saat t = 2 s
Vt = Vo + a t
Vt = 0 + 2,24 • 2
Vt = 4,48 m/s ← jwb (2)

jarak tempuh saat t = 2 s
S = Vo t + ½ a t²
S = 0 + ½ • 2,24 • 2²
S = 4,48 m ← jwb (4)


jawaban: (2) dan (4) benar