Math challenge. Please serve your way

panjang AC = √(4² + 3²) = √25 = 5 satuan panjang

AE = EF = FC = 5/3 satuan panjang

BD = AC = 5 satuan panjang

Luas EBFD = 1/2 * 5/3 * 5
= 25/6 satuan luas

PERSEGI PANJANG
AB = 4 cm
BC = 3 cm
AC^2 = AB^2 + BC^2
AC^2 = 4^2 + 3^2
AC^2 = 16 + 9
AC^2 = 25
AC = akar 25
AC = 5 cm
AE = EF = FC = (AC/3) = 5/3 cm
Diagonal1 (d1) = EF = 5/3 cm
Diagonal2 (d2) = BD = AC = 5 cm
L daerah segi empat EBFD = 1/2 × d1 × d2
= 1/2 × 5/3 × 5
= 25/6
= 4 1/6
jadi luas daerah segi empat EBFD adalah 4 1/6 cm^2