Matematika

Pertanyaan

Tentukan f'(-2) jika f(x)=6x³ - 4x²+3x-6

2 Jawaban

  • f(x)= 6x³ - 4x² + 3x - 6
    f'(x) = 18x² - 8x + 3
    f'(-2) = 18 (-2)² - 8(-2) + 3
            = 72 + 16 + 3
            = 91
  • f(x) = 6x³ - 4x² + 3x - 6

    f'(x) = 18x² - 8x + 3
    f'(-2) = 18(-2)² - 8(-2) + 3
    f'(-2) = 18(4) + 16 + 3
    f'(-2) = 72 + 16 + 3
    f'(-2) = 91

    Semoga berguna +_+

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