Tolong dong kak.. nomor 33

Lp bangun I (Prisma tanpa tutup)
= 8(8) + 2(10(8)) + 2(10(8))
= 64 + 160 + 160
= 384 cm²

Tinggi sisi tegak pada limas
t² = (8/2)² + (13-10)²
t² = 4² + 3²
t² = 25
t = 5 cm

Lp bangun II (Limas persegi tanpa alas)
= 4(1/2 * 5 * 8)
= 80 cm²

Lp seluruhnya
= 384 + 80
= 464 cm²

Jawaban B

s = 8 cm
tp = 10 cm
tl = 13 cm - 10 cm = 3 cm
ts^2 = (1/2(s))^2 + tl^2
ts^2 = (1/2(8))^2 + 3^2
ts^2 = 4^2 + 3^2
ts^2 = 16 + 9
ts^2 = 25
ts = akar 25
ts = 5 cm
L bangun I tanpa tutup = (s^2) + (4×s×tp)
= (8^2) + (4 × 8 × 10)
= 64 + 320
= 384 cm^2
L bangun II tanpa alas = 4×1/2×s×ts
= 4 × 1/2 × 8 × 5
= 80 cm^2
L seluruh bangun = L bangun I + L bangun II
= 384 + 80
= 464 cm^2
Jadi luas bangun itu adalah 464 cm^2