yg ngerti kasih tau dong. pake cara yaa :)

saya pakai latex, ya.

Gunakan aturan rantai.

[tex]$\begin{align}f(x)&=\frac{1}{x^6+1}-\frac{1}{3x^2} \\ &=(x^6+1)^{-1}-(3x^2)^{-1} \\ &=(x^6+1)^{-1} - (3x)^{-2} \\ f'(x)&=-(x^6+1)^{-1-1}\times(6x^5)-(-2)(3x)^{-2-1} \\ &=-6x^5(x^6+1)^{-2}+2\times(3x)^{-3} \\ &=\frac{-6x^5}{(x^6+1)^2}+\frac{2}{3x^3}\end{align}[/tex]