Tolong dijawab.. persamaan garis melalui titik (2,-3) dan tegak lurus terhadap garis 2x+5y-1=0 adalah..

2x + 5y - 1 = 0
5y = - 2x + 1
y = -2/5 x + 1

m = -2/5

Tegak lurus
m1 x m2 = -1
-2/5 x m2 = -1
m2 = 5/2

(2,-3)
y - y1 = m(x-x1)
y + 3 = 5/2 (x - 2)
Keduaruas ×2

2y + 6 = 5(x - 2)
2y + 6 = 5x - 10
0 = 5x - 10 - 2y - 6

5x - 2y - 16 = 0