Jika diketahui f(x)=4x dan f(g(x))=-x/2+1,mqka nilai g(x) adalah

f(x) = 4x
f(g(x)) = (-x/2) + 1
4g(x) = (-x/2) + 2/2
4g(x) = (-x+2)/2
g(x) = ((-x+2)/2) / 4
g(x) = (-x+2)/2 × 1/4
g(x) = (-x+2)/8

-->
g(x) = [tex] \dfrac{1}{8} (-x+2) [/tex]