pada percobaan lrmpar undi dua biah dadu sebanyak 216 kali frekuensi harapan munculnya mata adu berjumla genap adl

Mapel : Matematika
Kelas : IX SMP
Bab : Peluang

Pembahasan :
n(jumlah genap) = {(1,1)(1,3)(1,5)(2,2)(2,4)(2,6)(3,1)(3,3)(3,5)(4,2)(4,4)(4,6)(5,1)(5,3)(5,5)} = 15
n(s) = 6² = 36

Fh = P . n
Fh = 15/36 . 216
Fh = 5/12 . 216
Fh = 90 kali

Dua dadu berjumlah genap =
(1,1)(1,3)(1,5)
(2,2)(2,4)(2,6)
(3,1)(3,3)(3,5)
(4,2)(4,4)(4,6)
(5,1)(5,3)(5,5) = ada 15

Ruang sampel = 6^2 = 36

Peluang = 15/36
Peluang = 5/12

Frekuensi harapan = 5/12 × 216
Frekuensi harapan = 90 kali