jika bilangan bulat A dan B memenuhi x-12/6x^2-11x-10 = A/3x+2 + B/2x-5 , maka A+B = ?

Persamaan bentuk pecahan

(x-12) / (6x² -11x + 10) =  A/(3x+2) + B/(2x - 5)
(x-12) / (6x²- 11x + 10) = A(2x- 5) + B(3x+2) / (6x² -11x - 10)
 x - 12 = A(2x - 5)  + B(3x+ 2)
x -12 =  2x A - 5A + 3x B + 2B
x +(-12)  = x (2A+3B) +(-  5A + 2B)

2A + 3B = 1........kalikan 2
-5A + 2B= -12 ...kalikan 3
.
4A + 6B = 2
-15A + 6B = - 36
kuangkan
19A = 38--> A = 2 
2A + 3B = 1 --> B  = 1/3 (1 -2A)
B = 1/3(1 -4) --> B = - 1

A+B = 2 +(-1) = 1