Tolong sama caranya matematika

P = [ 1 2]
[ 1 3]
det(P) = 3 - 2 = 1

invers P = 1 [3 -2]
--- x [-1 1]
1
= [ 3 -2]
[-1 1]

2invers P = 2 [3 -2]
[-1 1 ]
= [6 -4]
[-2 2]

Jadi, x + y = 6 - 4 = 2
[6 -4] = [ x y]
[-2 2] [-z z]

Kalau ada yg ga paham tanya ya dek :)

Matriks
P = [1...2||1....3]
2 P⁻¹ = [x...y||-z....z]
x + y = 6 + (-4)
x + y = 2
(di lampiran)