diketahui persamaan kuadrat x^2+mx+2-2m^2 = 0 mempunyai x1 dan x2. jika 2(x1)+(x2) = 2 , nilai m adalah ....

x^2 + mx + 2 - 2m^2 = 0
x1 + x2 = -b/a = -m/1 = -m
2x1 + x2 = 2
x1 + x1 + x2 = 2
x1 + (-m) = 2
x1 = m + 2
Substitusi ke x^2 + mx + 2 - 2m^2 = 0
(m + 2)^2 + m(m + 2) + 2 - 2m^2 = 0
m^2 + 4m + 4 + m^2 + 2m + 2 - 2m^2 = 0
6m = -6
m = -1