Jika f(x) = 2x²+3/x-6 , maka f(0) + f'(0) adalah

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Berikan terima kasih

f(x) = (2x^2 + 3)/(x - 6)
f(0) = (2(0)^2 + 3)/(0 - 6)
f(0) = 3/(-6)
f(0) = - 1/2

f(x) = (2x^2 + 3)/(x - 6)

a = 2x^2 + 3 => a' = 4x
b = x - 6 => b' = 1

f'(x) = (a' . b - a . b')/(b)^2
f'(x) = (4x(x - 6) - (2x^2 + 3)(1))/(x - 6)^2
f'(x) = [(4x^2 - 24x) - (2x^2 + 3)]/[x^2 - 12x + 36]
f'(x) = [4x^2 - 24x - 2x^2 - 3]/[x^2 - 12x + 36]
f'(x) = [2x^2 - 24x - 3]/[x^2 - 12x + 36]
f'(0) = [2(0)^2 - 24(0) - 3]/[(0)^2 - 12(0) + 36]
f'(0) = -3/36
f'(0) = - 1/12

f(0) + f'(0)
= -1/2 + (-1/12)
= -6/12 - 1/12
= -7/12