Matematika

Pertanyaan

salah satu akar persamaan x2+6x+p=0 adalah dua kali akar yang lain. Maka nilai p adalah...

2 Jawaban

  • x1 = 2.x2

    x^2 + 6x + p = 0
    x1 + x2 --> 2x2 + x2 = 3x2
    = -b/a
    = -6/1
    3x2 = -6
    x2 = -6/3
    x2 = -2

    x1 = 2x2
    = 2(-2)
    = -4

    x1 . x2 = c/a
    (-4)(-2) = p/1
    8 = p

    Nilai p = 8
  • x^2 + 6x + p = 0

    a = 1
    b = 6
    c = p
    misal :
    x1 = 2(x2)

    x1 + x2 = - b/a
    2(x2) + x2 = - 6/1
    3(x2) = - 6
    x2 = -6/3
    x2 = -2

    x1 . x2 = c/a
    2(x2) . x2 = p/1
    2(x2)^2 = p

    p = 2(x2)^2
    p = 2(-2)^2
    p = 2 × 4
    p = 8

    Jadi nilai p adalah 8

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