Hasil limit dari gambar di bawah ini adalah,,, carany gmna ya?

limit
16 . d hosptal
dilampiran
= 0 + 2√(x²+ 15)
x= 7 --> 0 + 2√64) =  16

17.
lim(x->∞) √x {√(x-1) - √(x+1)}
lim(x→∞) √(x² -x) - √(x² + 1)
a= p= 1
b = -1
q = 1
limit = (b-q)/(2√a
limit = (-1 -1)/ (2√1)
limit= - 2/2= - 1

18.
lim(x->0) [ -4x + 4 sin 5x cos 5x ]/ [ 6x ]
lim(x->0)  [ -4 x + 2 sin 10x ] / [6x]
= - 4/6 + 20/6
= 16/6
= 2 2/3