Diketahui sistem persamaan 3x + 3y = 3 dan 2x - 4y = 14. Nilai dari 4x - 3y = ........jelaskan caranya

3x + 3y = 3 (x2)
2x - 4y = 14 (x 3)

6x + 6y = 6
6x - 12y = 42
_________ -
18y = - 36
y = -2

3x - 6 = 3
3x = 9
x = 3

4x - 3y = 4(3) - 3(-2) = 12 + 6 = 18

ELIMINASI =>Pers I dan II

3x + 3y = 3 (× 2)
2x - 4y = 14(× 3)

6x + 6y = 6
6x - 12y = 42
--------------------- -
.......18y = - 36
y = -36/18
y = -2

Subsitusikan y = -2 ke pers. I atau II
=>3x + 3y = 3
=>3x + 3(-2) = 3
=>3x - 6 = 3
=>3x = 3 + 6
=>3x = 9
=>x = 9/3
=>x = 3

4x - 3y = 4(3) - 3(-2)
= 12 + 6
= 18