jika diketahui log 3 = 0,4771 dan log 5 = 0,6990 maka a. log 0,36= b. log 135 = c. log 125/81 =

a.0,36=9/25
   log9/25=log9-log25
   log3²-log5²
   2.0,4771 - 2.0,6990
   -0,4438
b.135=27x5
   log27x5=log27+log5
   3.log3+log5=3.0,4771+0,6990=2,1303
c.125/81=log125-log81
   log5³-log3[tex] ^{4} [/tex]=3.0,6990-4.0,4771
   =0,1886