tolongg dong lihat dulu soalnya,, mtk

Bab Persamaan Kuadrat
Matematika SMP Kelas VIII

x² + x + c = 0
a = 1; b = 1; c = c

α² + β² = 3
(α + β)² - 2 αβ = 3
(-b/a)² - 2 . c/a = 3
(-1/1)² - 2 . c/1 = 3
1 - 2c = 3
2c = 1 - 3
c = -2/2
c = -1

jawabannya B

Mapel : Matematika
Kelas : X SMA
Bab : Persamaan Kuadrat

Pembahasan :
x² + x + c = 0

Berdasarkan Teorema Vietta
a . β = c/a
a . β = c/1
a . β = c

a + β = -b/a
a + β = -1/1
a + β = -1

Maka...
a² + β² = (a + β)² - 2aβ
3 = (-1)² - 2c
2c = 1 - 3
2c = -2
c = -1

Opsi B.