Carilah nilai turunan dari a. Y= (X²+2) (5X-3) b. Y= (X+2) / (2-5X)

b seharusnya
y'=f'(x)g(x)-f(x)g'(x)/g(x)^2
=1(2-5x)-(x+2)(-5)/(2-5x)^2
=2-5x+5x+10/25x^2-20x+4
=12/25x^2-20x+4

a. y = (x² + 2)(5x - 3)
U = x² + 2 => u' = 2x
V = 5x - 3 => v' = 5
y'(x) = u'v + uv'
y'(x) = 2x(5x - 3) + (x² + 2) 5
y'(x) = 10x² - 6x + 5x² + 10
y'(x) = 15x² - 6x + 10

b.
u = x + 2 => u' = 1
v = 2 - 5x => v' = -5
y'(x) = (u'v - uv') / v²
y'(x) = [1(2 - 5x) - (x + 2) -5] / (2 - 5x)²
y'(x) = [2 - 5x + 5x + 10] / 4 - 20x + 25x²
y'(x) = 12 / 25x² - 20x + 4