Lim 1-cos (x+4) . ---------------- = X->-4 x2+8x+16

Lim (1 - cos (x + 4)) / (x^2 + 8x + 16)
= Lim (2 sin^2 1/2 (x + 4)) / (x + 4)(x + 4)
= Lim 2 . (sin 1/2 (x + 4))/(x + 4) . (sin 1/2 (x + 4))/(x + 4)
= 2 . 1/2 . 1/2
= 1/2

Limit.

lim x→-4 [1 - cos (x + 4)] / (x² + 8x + 16)
= [1 - cos (-4 + 4)] / [(-4)² + 8(-4) + 16] = 0 / 0 ← Bentuk tak tentu

Gunakan aturan L'Hôpital!
= lim x→-4 -[-sin (x + 4) (1)] / (2x + 8)
= lim x→-4 sin (x + 4) / (2x + 8)
= sin (-4 + 4) / [2(-4) + 8)] = 0 / 0 ← Bentuk tak tentu lagi

Gunakan aturan L'Hôpital sekali lagi!
= lim x→-4 [cos (x + 4) (1)] / 2]
= cos (-4 + 4) / 2
= 1 / 2