tolong dijawab deadline

N : H = 14 : 3
massa mula2
m N2 = 28 gram
m H2 = 9 gram
massa yang bereaksi
m N2 = 28 gram
m H2 = 6 gram

massa NH3 (amonia) menggunakan hukum kekekalan massa
massa sebelum = massa sesudah
28 + 6 = 34 gram
m NH3 = 34 gram

m sisa H2 = 9 - 6 = 3 gram

9 - 6 = 3 gram
#Semoga Membantu