1. Diketahui fungsi f(x) = x² - 2x + 1 , g(x) = 2x - 1 dan (fog) (t) = 0. Nilai t yang memenuhi adalah... 2. Jika f(x) = x-5/2x+1 dan g(x) = √x² - 4 maka daerah

Langsung aja y

nomor 1
(fog)(x) = f{g(x)}

= g(x)² - 2g(x) + 1
= (2x - 1)² - 2(2x - 1) + 1
= 4x² - 4x + 1 - 4x + 2 + 1
= 4x² - 8x + 4

(fog)(t) = 4t² - 8t + 4

4t² - 8t + 4 = 0 → (÷4)
t² - 2t + 1 = 0
(t - 1)(t - 1) = 0
t = 1 dan t = 1

jadi nilai t = 1

nomor 2
(gof)(x) = g{f(x)}

= √(f(x)² - 4)
= √(x-5/2x+1)² - 4)
= √(x²-10x+25 / 4x²+4x+1) - 4)
= √(x²-10x+25-16x²-16x-4 / 4x²+4x+1)
= √(-15x²-26x+21 / 4x² + 4x + 1)
= √(21 - 26x - 15x² / 4x² + 4x + 1)

semoga berguna +_+